(2+(6/y))/(1-(9/y^2))

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Solution for (2+(6/y))/(1-(9/y^2)) equation: 


D( y )

y = 0

1-(9/(y^2)) = 0

y^2 = 0

y = 0

y = 0

1-(9/(y^2)) = 0

1-(9/(y^2)) = 0

1-9*y^-2 = 0

-9*y^-2 = -1 // : -9

y^-2 = 1/9

-2 < 0

1/(y^2) = 1/9 // * y^2

1 = 1/9*y^2 // : 1/9

9 = y^2

y^2 = 9 // ^ 1/2

abs(y) = 3

y = 3 or y = -3

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:-3) U (-3:0) U (0:3) U (3:+oo)

(6/y+2)/(1-(9/(y^2))) = 0

(6/y+2)/(1-9*y^-2) = 0

(6*y^-1+2)/(1-9*y^-2) = 0

6*y^-1 = -2 // : 6

y^-1 = -1/3

-1 < 0

1/(y^1) = -1/3 // * y^1

1 = -1/3*y^1 // : -1/3

-3 = y^1

y = -3

y in { -3} 

y belongs to the empty set

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